class Solution {
public int removeDuplicates(int[] nums) {
// base case: return if array have no el.
if(nums.length == 0) return 0;
int k = 1; // writer pointer , index = 0 is unique already, so start at 1
// i - reader pointer
for(int i=1; i<nums.length; i++) {
//LOGIC: check if curr. no. is diff than prev. no.
if(nums[i] != nums[i-1]) {
// diff? -> unique no. -> store
nums[k] = nums[i];
// same? -> not unique. -> dont do anything
// keep incrementing k
k++;
}
}
return k;
}
}