#include <iostream>
using namespace std;
int num = 25;
void sum(int a, int b) {
cout << num << endl;
int s = a + b;
cout << s << endl;
}
int main(){
sum(5, 4);
int s = 10;
cout << num << endl;
return 0;
}
class Solution { public int [] countOppositeParity ( int [] nums ) { // approach 1 - checks every pair int n = n...
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