#include <iostream>
using namespace std;
void oddOrEven(int num) {
if((num & 1)) {
cout << "even\n";
} else {
cout << "odd\n";
}
}
int main()
{
oddOrEven(5);
oddOrEven(8);
return 0;
}
Yes. I found an available transcript of the video and summarized it simply. The video is “How To Become Red Coder? (codeforces.com)” by Err...
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