void inorder(Node* root) {
if (root == NULL) return; // ✅ base case handled
inorder(root->left); // 🡐 left
cout << root->data << endl; // 🡐 root
inorder(root->right); // 🡐 right
}
Yes. I found an available transcript of the video and summarized it simply. The video is “How To Become Red Coder? (codeforces.com)” by Err...
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